STAAR question
There is a cylinder with the height of 4 in, the radius is 6 in, and pi=3. Then, there is a cube with the length 8 in, the width 9 in, and the height 10 in. How much bigger is the surface area of the cube than the cylinders? First, you would find the formula of a cylinder which is S=2*pi*r*h+ 2*pi*r squared. 2*pi=6. Times the radius which is 6=36. Times the height which is 4=144. Then you do the radius which is 6 squared which is 36. You multiply that by your product of the 2 times pi which is 6. 36 times 6 is 216. Then you do 216 +144 to get the surface area of the cylinder which is 360 in. Next, you would find the surface area of the cube. The formula for surface area of a cube is S=Ph+2B. First, you would find the perimeter of the base which is 9+9+8+8=34 times the height which is 10=340. Then, you would find the area of the base, which is 8*9=72 times 2=144+340=484. Then you would take the surface area of the cylinder and subtract that by the cubes surface area which is 124. Your awnser is 124.